A photon beam of energy 12.1eV is incident on a hydrogen atom . The orbit which electron of H-atom be excited is
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Answer:
It will be excited to 3 orbit
Explanation:
change in energy=Ef-Ei
Ein=13.4 ie in ground state
so Ef=1.5
which is energy for 3 orbit
by formula
E=13.6/n2
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