Question

A photon of 100 Å is absorbed by a body and it emitted the total energy in form of two photons of equal energy. The frequency of emitted photon is


1.5 × 1016 Hz


3 × 1015 Hz


6.4 × 1018 Hz


3.5 × 1012 Hz

Answer 1

Answer:

Use frequency*wavelength=velocity

Energy=Planck's constant*frequency

Hope it helps and please mark me as BRAINLIEST...

Answer 2

Answer:The right answer is 1.5 ×10^16

Explanation:

λ=100× 10^-10

Energy absorbed=energy emitted.

hc/λ=hν1+hν2.

given  ν1=ν2=ν

so  hc/λ=2hν.

c/λ=2ν.

ν= c/2λ

ν=3×10^8/2 ×100 ×10^_10

ν=1.5 ×10^16.