Question

A photon of 3000 Armstrong is absorbed by a gas and remitted two photons. One photon has wavelength of 4500 Armstrong. What would
be the wavelength of other photon?​

Answer 1

E =hc/λ

Wavelength of 1st photon = λ1

Wavelength of 2nd photon = λ2

Energy conservation-

E(Total) = E1 + E2 = Emitted energy

hc/ λ = hc/ λ1 + hc/ λ2

1/3000 = 1/7600 + 1/ λ2

1/ λ2 = (1/3000 – 1/7600)

λ2 = 4960 Angstrom = wavelength of second photon