Question

a photon of 300nm is absorbed by a gas and then emits two photons.one photon has a wavelength of 496nm,then the wavelength of second photon in wavelength is??
option(A)759,(859),(C)959,(659).

Answer 1

Given :

Wavelength of absorbed photon = 300nm

Wavelength of emitted photon A = 496nm

To Find :

We have to find wavelength of emitted photon B$.$

Solution :

★ Energy associated with a photon in terms of wavelength is given by

• E = hc/λ

h denotes planck's constant

c denotes speed of light in vacuum

⭆ Absorbed energy = Emitted energy

⭆ E = E(A) + E(B)

⭆ hc/λ = hc/λ₁ + hc/λ₂

⭆ 1/λ = 1/λ₁ + 1/λ₂

⭆ 1/λ₂ = 1/300 - 1/496

⭆ λ₂ = 148800/196

⭆ λ₂ = 759 nm

Cheers!