Question

a photon of 300nm is absorbed by a gas and then remitted two photons
one reemitted photon has wavelength of 400 nm calculate the energy of the other photon remitted out
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Answer 1

Answer:

Energy absorbed = Sum of energy of two quanta

hc/300×10−9​=hc/760×10−9​+hc/λ×10−9

On solving, we get,

vˉ(wavenumber)=/λ​=2.02×10−3m−

Explanation:

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Answer 2

Explanation:

Answer in the figure

Hope this will help you