Question

A photon of 400 nm is absorbed by a gas molecule and then the
molecule re-emits two photons. One re-emitted photon has
wavelength 500 nm. Assuming that there is no change in energy
of molecule, the wavelength of second re-emitted photon is​

Answer 1

Answer:

refer to attachment___

Answer 2

Given info : A photon of 400 nm is absorbed by a gas molecule and then the molecule re-emits two photons. One re-emitted photon has wavelength 500 nm.

To find : The wavelength of second re - emitted photon is ...

solution : if there is no change in energy.

initial energy = final energy

⇒energy of a photon absorbed by the gas molecule = energy of a photon of 500 nm wavelength + energy of the other photon

⇒hc/λ = hc/λ₁ + hc/λ₂

⇒1/λ = 1/λ₁ + 1/λ₂

here, λ = 400nm , λ₁ = 500 nm

so , 1/400 = 1/500 + 1/λ₂

⇒1/400 - 1/500 = 1/2000 = 1/λ₂

Therefore wavelength of second re - emitted photon is 2000 nm.

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