Question

A photon of energy 3.4 eV is incident on a metal having work function 2 eV. The maximum K.E. of photoelectrons is equal to(a) 1.4 eV(b) 1.7 eV(c) 5.4 eV(d) 6.8 eV

Answer 1

I suppose the answer is 1.4 eV

there is a relation of work function and energy that is ,

Energy of a photon = work function + kinetic energy

so applying this in to the given info

3.4 =2 + K.E

3.4 -2 = K.E

so, Kinetic energy of a photon is equal to 1.4 eV

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Answer 2

Given that,

Energy of a photon, E = 3.4 eV

Work function of a metal, W = 2 eV

To find,

The maximum kinetic energy of photoelectrons.

Solution,

Let K is the maximum kinetic energy of the photoelectron. The Einstein's photoelectric equation gives the relation between maximum kinetic energy, work function and energy of a photon as :

$K=E-W$

Putting all the values in above equation

$K=3.4-2\\\\K=1.4\ eV$

So, the maximum K.E. of photoelectrons is equal to 1.4 eV.

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A photon of energy 3.4 eV is incident on a metal having work function 2 eV. The maximum K.E. of photoelectrons is equal to?

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