A photon of frequency 300 Hz causes the emission of two photons. If the frequency of one of them is 100 Hz. What is the frequency of the other photon?
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Given:
Frequency of parent photon = 300 Hz
Frequency of first daughter photon = 100Hz
To find:
Frequency of the second daughter photon.
Solution:
Since the emission of photons follows the conservation rule of emission which is same as the conservation of momentum or conservation of energy. Therefore, in this case:
Frequency of parent photon = Frequency of daughter photons
300 Hz = 100 Hz + x
x = 200 Hz
Therefore, the frequency of the other photon will be 200 Hz.
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