A photon of wavelength 250 nm ejects an electron from a metal. The ejected electron has a de Broglie wavelength of 0.85 nm.
Answers
Answered by
10
(a) p = h / λ … mv = h / λ … (9.11 x 10–31)v = 6.63 x 10–34 / 0.85 x 10–9 … v = 8.56 x 105 m/s
K = ½ mv2 = ½ (9.11 x 10–31)(8.56 x 105)2 = 3.34 x 10–19 J
(b) K = Ein – φ … K = hc / λ – φ … 3.34 x 10–19 = 1.99 x 10–25 / 250 x 10–9 – φ … φ = 4.62 x 10–19 J = 2.89 eV
(c) From E = hc / λ, a bigger λ means a smaller energy. The X emission of 400 nm is a smaller energy than the 250 nm photon. Since the photon was “created” from this transition, it must be an emission so we should go down energy levels with an energy difference larger than the X level difference. This would be transition d.
K = ½ mv2 = ½ (9.11 x 10–31)(8.56 x 105)2 = 3.34 x 10–19 J
(b) K = Ein – φ … K = hc / λ – φ … 3.34 x 10–19 = 1.99 x 10–25 / 250 x 10–9 – φ … φ = 4.62 x 10–19 J = 2.89 eV
(c) From E = hc / λ, a bigger λ means a smaller energy. The X emission of 400 nm is a smaller energy than the 250 nm photon. Since the photon was “created” from this transition, it must be an emission so we should go down energy levels with an energy difference larger than the X level difference. This would be transition d.
Answered by
0
HEY BUDDY HERE IS UR ANSWER !!
(a) p = h / λ
mv = h / λ (9.11 x 10–31)
v = 6.63 x 10–34 / 0.85 x 10–9
v = 8.56 x 105 m/s
K = ½ mv2 = ½ (9.11 x 10–31)(8.56 x 105)2 = 3.34 x 10–19 J
(b) K = Ein – φ … K = hc / λ – φ ..3.34 x 10–19 = 1.99 x 10–25 / 250 x 10–9 – φ … φ = 4.62 x 10–19 J = 2.89 eV
(c) From E = hc / λ, a bigger λ means a smaller energy. The X emission of 400 nm is a smaller energy than the 250 nm photon. Since the photon was “created” from this transition, it must be an emission so we should go down energy levels with an energy difference larger than the X level difference. This would be transition d.
》 》 BE BRAINLY 《 《
(a) p = h / λ
mv = h / λ (9.11 x 10–31)
v = 6.63 x 10–34 / 0.85 x 10–9
v = 8.56 x 105 m/s
K = ½ mv2 = ½ (9.11 x 10–31)(8.56 x 105)2 = 3.34 x 10–19 J
(b) K = Ein – φ … K = hc / λ – φ ..3.34 x 10–19 = 1.99 x 10–25 / 250 x 10–9 – φ … φ = 4.62 x 10–19 J = 2.89 eV
(c) From E = hc / λ, a bigger λ means a smaller energy. The X emission of 400 nm is a smaller energy than the 250 nm photon. Since the photon was “created” from this transition, it must be an emission so we should go down energy levels with an energy difference larger than the X level difference. This would be transition d.
》 》 BE BRAINLY 《 《
Similar questions