Chemistry, asked by NRR0164, 7 months ago

a photon of wavelength 4×10^-7 kinetic energy and velocity of photoelectron

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Answered by TheRiskyGuy

Answer:

Substituting the values in the given expression of E: Hence, the energy of the photon is 4.97 × 10–19 J. Hence, the kinetic energy of emission is 0.97 eV. Hence, the velocity of the photoelectron is 5.84 × 105 ms–1.

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a photon of wavelength 4×10^-7 kinetic energy and velocity of photoelectron​

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a photon of wavelength 4×10^-7 kinetic energy and velocity of photoelectron