a photon of wavelength 4 into 10 to the power minus 7 metre strike strikes on a metal surface the work function of the metal surface is 2.93 electron volt calculate the energy of the photon kinetic energy of the emitted electron velocity of the photoelectron
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firstly use formula E=hc/lambda u will get answer as 497*10^-9 J then to find kinetic energy we formula 1/2 mv^2 which is also equal to hv-hvo which is equal to (E-W)eV-2.13eV u will get answer as 0.97eV which is the final answer
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