A photon of wavelength 99 nm falls on a metal plate of work function 1.0 eV. The wavelength of the fastest emitted photoelectron is (given h = 6.6 ×10–34 Js, mass of electron (m = 9.1×10–31 kg)
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The wavelength of the fastest emitted photoelectron is 3.6A°
Wavelength of the photons = 99nm
= 99 * 10 ('-9) m
Energy of the photon = (hc)/Д ( Д =Wavelength)
= 2 * 10('-11) J
Ke max = hv-Work function
Work function = 1 ev
Ke max = 2 * 10('-18) - 1.6 * 10('-19)
= 1.84 * 10('-18)
Ke max = p²/2m (p = maximum momentum)
From de broglie Д = h/p
p = √(2m kEmax)
Д = 3.6 A°
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