a photosensitive surface emits photelectrons when red light falls on it. Will the surface photoelectrons when blue light is incident on it. Give reason.
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Answered by
25
We know E=hc/l
E is the energy
l is the wavelength
As red has the most biggest wavelength
So it has least energy
Blue has small wavelength thus more energy
And if at that energy the photoelectron are released then at greater energy they must be released...
E is the energy
l is the wavelength
As red has the most biggest wavelength
So it has least energy
Blue has small wavelength thus more energy
And if at that energy the photoelectron are released then at greater energy they must be released...
Answered by
8
Work function=hC/£
h- Planck's constant
C- velocity of light
£- wave length
When photoelectrons are emitted for red light the work function is hC/£(red)>work function
When blue light is used E=hC/£(blue)
£(red)>£(blue)
This indicates that electronic emission is possible
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