Physics, asked by vedangrc, 9 months ago

A physical quantity is found to be 10^7 J / m^3. Find its value in erg/cm^3.

Answers

Answered by yadavsaurav4463
5

Explanation:

Your

answer is here i.e.=

10^8

Attachments:
Answered by Anonymous
0

The value is 10⁸erg/cm³.

Given : A physical quantity is found to be 10⁷J/m³.

To find : Its value in erg/cm³.

Solution :

We can simply solve this numerical problem by using the following mathematical process. (our goal is to calculate its value in erg/cm³)

Here, we need the following two mathematical relationships :

  • 1 J = 10⁷ erg
  • 1 m³ = 10⁶ cm³

So,

= 1J/m³

 =  \frac{1J}{1 {m}^{3} }

 =  \frac{ {10}^{7} \: erg }{ {10}^{6}   \: {cm}^{3} }

= 10 erg/cm³

Now,

1 J/m³ = 10 erg/cm³

So,

10⁷ J/m³ = (10⁷ × 10) erg/cm³

or,

10⁷ J/m³ = 10⁸ erg/cm³

(This will be considered as the final result.)

Hence, the value is 10⁸erg/cm³.

#SPJ3

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