Question

A physical quantity is measured as q = (2.1±0.5). calculate the percentage error in (i)q² and (ii) 3q.

Answer 1

(i) % error in q = $\frac{0.5}{2.1} \times 100= 23.81%$
    there fore % error in $q^{2}$ = $2 \times 23.81 = 47.62%$
(ii) % error in 3q = % error in q = 23.81%

Answer 2

Hope it helps you..