Question

A physical quantity is represented by x=mlt.If the percentage error in the measurement of m, l, t are 2alpha %,beta %,3gamma % respectively then maximum percentage error in x is

Answer 1

Answer:

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Answer 2

Given that,

A physical quantity is represented by :

$X=m\times l\times t$

The the percentage error in the measurement of m, l, t are $2\alpha \%, 2\beta \%\ and\ 2\gamma \%$

To find,

The maximum percentage error in X.

Solution,

The percentage error in X is given by :

$\dfrac{\Delta X}{X}=\dfrac{\Delta m}{m}+\dfrac{\Delta l}{l}+\dfrac{\Delta t}{t}\\\\\dfrac{\Delta X}{X}=2\alpha +\beta +3\gamma$

So, the percentage error in X is  $2\alpha +\beta +3\gamma$.

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Percentage error

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