Physics, asked by faizatg9582, 11 months ago

A physical quantity P is described by the relation P = a1/2 b2 c3 d–4 If the relative errors in the measurement of a, b, c and d respectively, are 2%, 1%, 3% and 5%, then the relative error in P will be :

Answers

Answered by help7oo645o984
13

Answer:

relative error = 1/2 x 2℅ + 2 x 1℅ + 3× 3℅ +4 × 5℅

= 1/100 + 2/100+9/100+20/100= 32℅

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