Question

A physical quantity P is given by p= [A^3.B^2/3]/(C^4.D^1/2) where A,B,C,D are 1%,3%,1%,2% , the relative percentage error is

Answer 1

Answer:

As P=(a^3b^2)/(c^4d^1/2)

a^3     b^2   c^4   d^1/2

ΔP= 3Δa/a + 2Δb/b + 4Δc/c + 1/2Δd/d

Δa/a=1% Δb/b=3% Δc/c=1% Δd/d=2%

ΔP=(3x1) + (2x3) + (4x1) + (1/2x2)

ΔP= 3 + 6 + 4 + 1

ΔP=14%