Question

A physical quantity P is given by P= A³ B¹2 C-4D3/2 quantity which brings the maximum percentage error in Pis (All the quantities have equal percentage of error) 1.A 2.B 3.C 4.D​

Answer 1

Given :    A physical quantity P is given by

$P =A^3B^1C^{-4}D^{\frac{3}{2}}$

All the quantities have equal percentage of error

To Find :  quantity which brings the maximum percentage error

Solution:

$P =A^3B^1C^{-4}D^{\frac{3}{2}}$

$P = \dfrac{A^3B^1D^{\frac{3}{2}}}{C^{4}}$

Any Quantity   Aⁿ     gives  percentage error =  | n | % error of A

A³   % error  = 3  *  % error of A

B¹   % error  = 1 *  % error of B

C⁻⁴  % error  =  4 *   % error of C

$D^\frac{3}{2}$ % error  =  (3/2) *   % error of D

As % error of A , B , C and D is same

Hence 4 *   % error of C  will be maximum

so  C  brings the maximum percentage error

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