a physical quantity P is given by P=(A³B½)(C-¼Dto the power 3/2 ) Which among the quantity A, B, C,D has the maximum %error in P
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Answer:
P=
C
−4
D
3/2
A
3
B
1/2
⇒
P
ΔP
=
A
3ΔA
+
2
1
B
ΔB
+
C
4ΔC
+
2
3
D
ΔD
.
∴ C brings max % error in P.
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