Physics, asked by 2201khushitiwari, 9 months ago

A physical quantity P is related to four observables a,b,c and d as follows P=a^3b^2÷(√cd). The percentage error in measuring a,b,c,d are 1%,3%,4% and 2% respectively. What is percentage error in calculation of P.
I'll mark you as brainliest...​

Answers

Answered by deepabpl02
0

Answer:

3.8

Explanation:

P=

c

d

a

3

b

2

Maximum fractional error in P is given by

P

ΔP

=±[3

a

Δa

+2

b

Δb

+

2

1

c

Δc

+

d

Δd

]

On putting above value:

100

13

=0.13

Percentage error in P=13 %

Value of P is given as 3.763.

By rounding off the given value to the first decimal place, we get P=3.8.

Similar questions