Physics, asked by Anonymous, 1 month ago

A physical quantity P is related to four observables a,b,c,d as follows: P= a^3 b^2 / ( √cd) The percentage error of measurement in a,b,c,d are 1%,3%,4%,2%respectively . What is the percentage error in the quantity P ? If the value of P calculated using the above relation turns out to be 3.763,to what value should you round off the result?​

Answers

Answered by Anonymous
4

Explanation:

The percentage error in P is 13%. Hence, The percentage error in P is 13%.

Answered by lovinglavisha
3

physical quantity P is related to four observables a,b,c,d as follows: P= a^3 b^2 / ( √cd) The percentage error of measurement in a,b,c,d are 1%,3%,4%,2%respectively . What is the percentage error in the quantity P ? If the value of P calculated using the above relation turns out to be 3.763,to what value should you round off the result?

sorry di but idk

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