A physical quantity Q is found to depend on observables x, y and z, obeying relation Q=x3y2/z. The percentage error in the measurements of x, y and z are 1%, 2% and 4% respectively. What is percentage error in the quantity Q.
Answers
Answer -
Suppose ,
Percentage error in value of x = n (percentage error in value of a) + m (percentage error in value of b)
For the given question -
Percentage error in x = 1%
Percentage error in y = 2%
Percentage error in z = 4%
Percentage error in Q = 3 ( percentage error in x ) + 2 ( percentage error in y ) + 1 ( percentage error in z )
Percentage error = 3 ( 1% ) + 2 ( 2% ) + 1( 4% )
Percentage error = 3% + 4% + 4%
Percentage error = 11%
Explanation:
Suppose , \rm x = \frac{ {a}^{n} }{b^m}x=
b
m
a
n
Percentage error in value of x = n (percentage error in value of a) + m (percentage error in value of b)
For the given question -
\rm Q = \dfrac{{x}^{3}{y}^{2}}{z}Q=
z
x
3
y
2
\implies⟹ Percentage error in x = 1%
\implies⟹ Percentage error in y = 2%
\implies⟹ Percentage error in z = 4%
Percentage error in Q = 3 ( percentage error in x ) + 2 ( percentage error in y ) + 1 ( percentage error in z )
Percentage error = 3 ( 1% ) + 2 ( 2% ) + 1( 4% )
Percentage error = 3% + 4% + 4%
Percentage error = 11%
\boxed{\rm\pink{Percentage \:error\: in\: value\: of\: Q = 11\%}}
PercentageerrorinvalueofQ=11%