A physical quantity S= a^3 b^1/2. The percentage error in the measurement of a and b are 1% and 4% respectively. What is the percentage error in the quantity S.
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Here, d1=2.620,d2=2.625,d3=2.628,d4=2.626
Mean of the diameter, d=42.620+2.625+2.628+2.626=2.625
So, Δd1=d1−d=2.620−2.625=−0.005
Δd2=d2−d=2.625−2.625=0
Δd3=d3−d=2.628−2.625=0.003
Δd4=d4−d=2.626−2.625=0.001
Thus, mean absolute error =4∣Δd1∣+∣Δd2∣+∣Δd3∣+∣Δd4∣=40.005+0
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