Physics, asked by jeffrinjoshy, 8 months ago

A physical quantity X is given by

X= A^2b^3÷c√d If the percentage errors of measurement in
a,b,c and d are4%, 2%, 3% and 1% respectively, then
calculate the percentage error in X.

Answers

Answered by kalashjain03
1

Explanation:

P=cda3b2

Maximum fractional error in P is given by

PΔP=±[3aΔa+2bΔb+21cΔc+dΔd]

On putting above value:

        =±10013=0.13

Percentage error in P=13 %

Value of P is given as 3.763.

By rounding off the given value to the first decimal place, we get P=3.8.

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