Question

A physical quantity X is related to four measurable quantities a, b, c and d as given X = a^2b^3c^5/2d^–2. The percentage error in the measurement of a, b, c and d are 1%, 2%, 3% and 4%, respectively. What is the percentage error in quantity X ? If the value of X calculated on the basis of the above relation is 2.763, to what value should you round off the result​

Answer 1

Answer:

X=$a^2*b^3*c^5/2d^-^2$

Percentage error in X is

ΔX/x$*100$ = [2(  Δa/a) + 3(Δb/b) +5/2 (Δc/c) + 2( Δd/d)]$*100$

= 2* 1 + 3*2 + 5/2*2 + 2*4

= 21%