Question

A physical quantity y is given by y = ab^2/c and the percentage errors in the measurement of a, b and c is 2%, 1% and 1% respectively. The percentage error in y will be?

Answer 1

Explanation:

since y=ab²/c

here percentage error in a, b, c are 2%,1%,1%

so,

percentage error in y=

percentage error in {a+b²+c}

percentage error in y=2%+1%²+1%

percentage error in y=4%