Physics, asked by Adityarocks6308, 1 year ago

A physical quantity z is given by the relation z=As in(kx-omega t). If x and the denotes displacement and time respectively then dimension of (omega) /k is

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Answered by abhi178
5

given, A physical quantity, z = Asin(kx - ωt) , where x and t denotes displacement and t.

we know,

  • dimension of x = [L]
  • dimension of t = [T]

from dimensional analysis,

dimension of kx = dimension of ωt = dimensionless [ because angle of any trigonometric functions must be dimensionless quantity ]

so, dimension of k = 1/dimension of x

or, dimension of k = [L-¹]

similarly, dimension of ω = 10/dimension of t = [T-¹]

so, dimension of ω/k = [T-¹]/[L-¹] = [LT-¹]

hence, dimension of (ω/k) = [LT-¹]

Answered by bharathjeeva2002
2

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