Question

A physicist calculated the wall width of half brick thickness (the brick is laid in a flat position lengthwise called strecher position), as (1.36+-0.1)cm.
And one brick thickness (the brick is placed in header position) as (23.6+-0.1)cm.
Calculate the difference in width of walls with uncertainty in it.
It's numerical of physics.
I asked this question multiple times but No one answered.
The one who will will be legend...​

Answer 1

Answer:

one brick thickness (the brick is placed in header position) as (23.6+-0.1)cm.

Calculate the difference in width of walls with uncertainty in it.

It's numerical of physics.

I asked this question multiple

Explanation:

one brick thickness (the brick is placed in header position) as (23.6+-0.1)cm.

Calculate the difference in width of walls with uncertainty in it.

It's numerical of physics.

I asked this question multiple

Answer 2

Answer:

the answer is (10 _+ 0.2)

Explanation:

here the full break wall = T2

half break wall =T1

so the ans is

T2-T1=(23.6_+0.1)-(13.6_+0.1)

=(23.6-13.6)_+0.1+0.1

=(10_+0.2)