A picnic basket falls out of a hot air balloon that is traveling horizontally at 14 m/s. The hot air balloon is at an altitude of 250 m. Where does the picnic basket land relative to where it was dropped from?
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Answer!
V= 14m/s
a= -9.8 m/s^2
v=0
Delta y=250
V^2=v^2+2a delta y
V= = √(14^2 +2(−9⋅8)×(-250)
V= -73.6 m/s......
BTS ARMY!!!
V= 14m/s
a= -9.8 m/s^2
v=0
Delta y=250
V^2=v^2+2a delta y
V= = √(14^2 +2(−9⋅8)×(-250)
V= -73.6 m/s......
BTS ARMY!!!
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