Question

A picture and its frame have dimensions as shown as above
a)Find an expression for the area of the frame, in factored form
b)Determine the area of the frame when s=15 cm.​

Answer 1

Answer:

hope it helps...............................

Step-by-step explanation:

Answer 2

Given:

thickness of the frame$=4$

length of the outer side of the picture$=8s$

Solution:

Part a)

Find the expression for the area of the frame.

Area of the frame$\[ =$ area of the outer square $-$area of the inner square

                            $\[\begin{array}{l} = {\left( {8s} \right)^2} - {\left( {8s - 8} \right)^2}\\ = 64{s^2} - 64{s^2} + 128s - 64\\ = 128s - 64\end{array}\]$

Therefore, the expression for the area of the frame is  $128s-64$.

Part b)

Find the area of the frame if $s=15cm$.

area of the frame  $=128s-64$.

                              $\[\begin{array}{l} = 1920 - 64\\ = 1856c{m^2}\end{array}\]$

hence , the area of the frame is $\[1856c{m^2}\]$.