Question

a picture frame has dimensions 80 cm and 60 cm . what is the length of its diagonals?

Answer 1

By Pythagoras theorem,

$diagonal = \sqrt{80 {}^{2} + {60}^{2} } \\ diagonal = \sqrt{6400 + 3600} \\ diagonal = \sqrt{10000} \\ diagonal = 100cm$

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@zaqwertyuioplm :)

Answer 2

dfgonal=root 3× side

for square