a picture frame has dimensions 80 cm by 60 cm . ehat is the length of its diagnol .
Answers
Answered by
29
The picture frame is a rectangle.
so it's diagonal=√{(80^2)+(60^2)}
=√(6400+3600)
=√10000
=100. ans
so it's diagonal=√{(80^2)+(60^2)}
=√(6400+3600)
=√10000
=100. ans
Answered by
16
QUESTION ----- a picture frame has dimensions 80 cm by 60 cm . ehat is the length of its diagonal ?
ANSWER -----
THE PICTURE FRAME IS A RECTANGLE
This implies that It has 90° angle at its corner
If you draw the diagonal then you will get 2 right angle triangles whose
Base = 80 cm
Height = 60 cm
Hypotenuse = ?
USING PYTHAGORAS THEOREM,
(Hypotenuse) ^2 = (Base) ^2 + (Height) ^2
( Hypotenuse) ^2 = 80^2 + 60^2
( Hypotenuse) ^2 = 6400 + 3600
( Hypotenuse) ^2 = 10000
Hypotenuse = √10000
Hypotenuse = 100 cm
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
ANSWER = 100 cm
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
ANSWER -----
THE PICTURE FRAME IS A RECTANGLE
This implies that It has 90° angle at its corner
If you draw the diagonal then you will get 2 right angle triangles whose
Base = 80 cm
Height = 60 cm
Hypotenuse = ?
USING PYTHAGORAS THEOREM,
(Hypotenuse) ^2 = (Base) ^2 + (Height) ^2
( Hypotenuse) ^2 = 80^2 + 60^2
( Hypotenuse) ^2 = 6400 + 3600
( Hypotenuse) ^2 = 10000
Hypotenuse = √10000
Hypotenuse = 100 cm
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
ANSWER = 100 cm
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
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