Question

a picture frame has it's length 8cm longer than it's width. it has an inner 1-cm boundary such that a maximum 660 cm² picture may fit into it. Find the dimensions of the frame and show step by step process​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

A picture frame has it's length 8cm longer than it's width.

$l = b + 8$

It has an inner 1-cm boundary such that a maximum 660 cm² picture may fit into it.

$(l - 2)(b - 2) = 660 \\ (b + 8 - 2)(b - 2) = 660 \\ (b + 6)(b - 2) = 660 \\ {b}^{2} + 4b - 12 = 660 \\ {b}^{2} + 4b - 672 = 0$

Solving the quadratic equation, the dimension of frame we get,

$b = 24 \: cm \\ and \\ l = 24 + 8 = 32 \: cm$