Question

A picture is 7by 3/5 cm wide. How much should it be trimmed to fit in a frame 7 by 3/10cm wide?

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Answer 1

Answer:

21/10 cm²

Step-by-step explanation:

Area of the picture = 7*3/5 = 21/5 cm²

Area of frame = 7*3/10 = 21/10 cm²

Area of picture - ? = Area of frame

21/5 - ? = 21/10

So,Therefore ,

? = 21/5 - 21/10 = 42/10 - 21/10 = 21/10 cm²

Hope it helps !!!!

Answer 2

$\sf\large{\red{\underbrace{Answer \implies \dfrac{3}{10}\:cm}}}$

$\sf\large{\underline{There\:are\:two\:things\:here:-}}$

$\sf\large{(1). \:Picture\: and,}$

$\sf\large{(2).\: Frame}$

$\sf\large{\underline{\underline{Given:}}}$

$\sf\large{ To\:fit\:the\:frame\:picture\:cannot\:be}$$\sf\large{more\:than\:7 \dfrac{3}{10}\:cm\:wide.}$

$\sf\large{\underline{\underline{So:}}}$

$\sf\large{ \: \: \: \: \: \: \: Picture\:has\:to\:be\:trimmed}$

$\sf\large{Now,}$

$\sf\large{Amount\:to\:be\:trimmed = 7 \dfrac{3}{5} - 7 \dfrac{3}{10}}$

$\sf\large{ \: \: \: \: \: \: \: \: \: \: \: \: = (7 + \dfrac{3}{5}) - (7 + \dfrac{3}{10})}$

$\sf\large{ \: \: \: \: \: \: \: \: \: \: \: \: = (7 - 7) + ( \dfrac{3}{5} - \dfrac{3}{10})}$

$\sf\large{ \: \: \: \: \: \: \: \: \: \: \: \: = 0 + ( \dfrac{3}{5} - \dfrac{3}{10})}$

$\sf\large{ \: \: \: \: \: \: \: \: \: \: \: \: = \dfrac{3}{5} - \dfrac{3}{10}}$

$\sf\large{ \: \: \: \: \: \: \: \: \: \: \: \: = \dfrac{3 × 10-3×5}{5×10}}$

$\sf\large{ \: \: \: \: \: \: \: \: \: \: \: \: = \dfrac{30-15}{50}}$

$\sf\large{ \: \: \: \: \: \: \: \: \: \: \: \: = \dfrac{15}{50}}$

$\sf\large{ \: \: \: \: \: \: \: \: \: \: \: \: = \dfrac{3}{10} \:cm}$

$\sf\large{\underline{\underline{Therefore,}}}$

$\sf\large{ \: \: \: \: Picture\: has\:to\:be\:trimmed\: \dfrac{3}{10}\:cm.}$