Question

A picture is painted on a cardboard 8 cm long and 5 cm wide such that there is a margin of 1.5 cm along each of its sides. Find the total area of the margin.​

Answer 1

Step-by-step explanation:

Length of painted cardboard=8=8 cm and breadth of painted card =5=5cm

Since, there is a margin of 1.51.5cm long from each of its side.

Therefore reduced length

=8-(1.5+1.5)=8-3=5=8−(1.5+1.5)=8−3=5cm

And reduced breadth

=5-(1.5+1.5)=5-3=2=5−(1.5+1.5)=5−3=2cm

\therefore∴ Area of margin==Area of cardboard(ABCD)-−Area of cardboard(EFGH)

=(AB\times AD)-(EF\times EH)=(AB×AD)−(EF×EH)

=(8\times 5)-(5\times 2)=(8×5)−(5×2)

=40-10=40−10

=30cm^2=30cm2

Answer 2

$\huge\mathfrak{\underline{Correct\:question}}$

A picture is painted on a cardboard 8 cm long and 5 cm wide such that there is a margin of 1.5 cm along each of its sides. Find the total area of the margin.

______________________________

Given that:-

• A picture is painted on a cardboard

• Length of picture = 8cm

• Width of picture = 5cm

• There is a margin of 1.5 cm along each of its sides.

To find:-

• Total area of the margin

Answer:-

$\bold{STEP-BY-STEP-EXPLANATION}$

From the question it is given that,

Length of the cardboard (L) = 8 cm

Breadth of the cardboard (B) = 5 cm

Then,

Area of the cardboard = length × breadth

= 8 × 5

= 40 cm^2

From the figure,

The new length and breadth of the cardboard when margin is not included is 5 cm and 2 cm respectively.

New area of the cardboard = 5 × 2

= 10 cm^2

The area of margin = Area of the cardboard when margin is including – Area of the cardboard [margin not included]

= 40 – 10

= 30 cm^2

Therefore, total area of margin = 30cm^2

#BAL

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