Math, asked by rajendranarumugam87, 1 year ago

A picture is painted on a celling of marriage hall whose length and breadth are 18m and 7m respectively there is a border of 10 cm along each of its sides find the area of the border

Answers

Answered by bhagyashreechowdhury
10

If a picture is painted on a ceiling of marriage hall whose length and breadth are 18 m and 7 m respectively and there is a border of 10 cm along each of its sides then the area of the border is 4.96 m².

Step-by-step explanation:

Step 1:

Length of the ceiling, l = 18 m

Breadth of the ceiling, b = 7 m

Area of the ceiling = l * b = 18 * 7 = 126 m²

Step 2:

We are given that there is a border along each side of the ceiling, i.e., the width of the border, w = 10 cm = 0.1 m

Now,  

The length of the ceiling excluding the border,

= l – 2w

= 18 – (2*0.1)

= 17.8 m

And,

The breadth of the ceiling excluding the border,

= b – 2w

= 7 - (2*0.1)

= 6.8 m

Area of the ceiling excluding the border

= [l – 2w] * [b – 2w]

= 17.8 – 6.8

= 121.04 m²

Step 3:

Thus,  

The area of the border is given by,

= [Area of the ceiling] – [Area of the ceiling excluding the border]

= 126 m² – 121.04 m²

= 4.96 m²

Hope this is helpful!!!!

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