A picture is painted on a celling of marriage hall whose length and breadth are 18m and 7m respectively there is a border of 10 cm along each of its sides find the area of the border
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If a picture is painted on a ceiling of marriage hall whose length and breadth are 18 m and 7 m respectively and there is a border of 10 cm along each of its sides then the area of the border is 4.96 m².
Step-by-step explanation:
Step 1:
Length of the ceiling, l = 18 m
Breadth of the ceiling, b = 7 m
∴ Area of the ceiling = l * b = 18 * 7 = 126 m²
Step 2:
We are given that there is a border along each side of the ceiling, i.e., the width of the border, w = 10 cm = 0.1 m
Now,
The length of the ceiling excluding the border,
= l – 2w
= 18 – (2*0.1)
= 17.8 m
And,
The breadth of the ceiling excluding the border,
= b – 2w
= 7 - (2*0.1)
= 6.8 m
∴ Area of the ceiling excluding the border
= [l – 2w] * [b – 2w]
= 17.8 – 6.8
= 121.04 m²
Step 3:
Thus,
The area of the border is given by,
= [Area of the ceiling] – [Area of the ceiling excluding the border]
= 126 m² – 121.04 m²
= 4.96 m²
Hope this is helpful!!!!
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