A piece if wire of resitance 20 is drawn out so that its length is incresed to twice its original length. calculate the resitance
of the wire in the situation
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A piece of wire of resistance 20 Omega is drawn so that its length is increased to twice is original length. ... When the length becomes 2l and cross-sectional area is A/2. Rnew=ρ(2l)A/2=4(ρl/A)=4(20Ω)=80Ω.
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