Question

a piece of a wire is bent in the shape of an equilateral triangle of its a 6.6 m it it is we went to the form of a circular ring what is the diameter of the Ring

Answer 1

as the same wire is bent into circle therefore ,
the perimeter of equilateral triangle = circumference of circle...........
6.6+6.6+6.6=2*22/7*r
19.8*7/44=r
138.6/44 =r
3.15 cm = r .....answer

hope it helps you.....

Answer 2

perimeter=6.6×3=19.8m

C=2πr
19.8=2×22/7×r
19.8×7/44=r
138.6/44=r
3.15=r
d=2r
d=2×3.15
d=6.3m