Math, asked by safinazmallick50, 3 months ago

a piece of a wire is bent to form a rectangle of are 72cm². if its length is twice its breadth. find the length of the wire​

Answers

Answered by Anonymous
28

Step-by-step explanation:

Answer

Let the length and breadth of rectangle be 7x and 5x respectively.

perimeter of rectangle=length of wire

∴2(7x+5x)=72⇒24x=72⇒x=3

∴ Length of rectangle= 7×3=21cm

Breadth of rectangle =5×3=15

Area of rectangle =21×15=315cm

2


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Answered by prabhas24480
1

Answer :

The required length of the wire = 36 cm

Step-by-step explanation :

Given :

A piece of wire is bent to form a rectangle of area 72 cm²

the length is twice its breadth

To find :

the length of the wire

Solution :

Let L cm be the length of the rectangle and B cm be the breadth of the rectangle.

 L = 2B

Area of the rectangle = length × breadth

 72 cm² = L × B

 72 = 2B × B

 2B² = 72

  B² = 72/2

  B² = 36

  B = √36

  B = 6 cm

The breadth of the rectangle = 6 cm

The length of the rectangle = 2(6) = 12 cm

we have to find the length of the wire. Let it be "l cm"

Since the wire is bent to form a rectangle, the length of the wire is equal to the perimeter of the rectangle.

     

So, finding the perimeter of the rectangle :

➙ Perimeter of the rectangle = 2(Length + breadth)

➙ Perimeter of the rectangle = 2 ( L + B)

➙ Perimeter of the rectangle = 2 (12 + 6)

➙ Perimeter of the rectangle = 2 (18)

➙ Perimeter of the rectangle = 36 cm

The length of the wire is equal to the perimeter of the rectangle.

Therefore, the length of the wire = 36 cm

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