Question

A piece of alloy weighing 5kg has equal quantities of tin and copper. How much tin should be add to the alloy to make the ratio of tin to copper as 60:40?​

Answer 1

Step-by-step explanation:

Let 100 gm of alloy A and 100 gm of alloy B

Gold in alloy A=

9

7

×100

copper in alloy A=

9

2

×100

Gold in alloy B=

18

7

×100

Copper in alloy B=

18

11

×100

Gold in alloy C=

9

700

+

18

700

=

18

2100

Copper in alloy C=

9

200

+

18

1100

=

18

1500

Ratio of copper and iron in alloy C=

18

2100

:

18

1500

7:5

Answer 2

$\frac{5}{4} \: = \: 1.25 \: kg$

Step-by-step explanation:

Since, both are in equal quantities

Therefore, mass of :-

Tin = 2.5 kg

Copper = 2.5 kg

Now, Tin is only to be added, so amount of Copper would be constant.

Therefore,

$\frac{5}{2} = m \times \frac{40}{100} \\ \: \: \: (m \:is \: the \: total \: mass \: after \: adding \:tin)$

$m= \frac{25}{4} = 6.25 \: kg$

Now, on subtracting the inital mass of the alloy, from the final mass, we'll get the mass of tin to be added in the initial alloy

$6.25 - 5 = 1.25 \: kg$

That's all.