A piece of aluminium of density 2.6g/cm^3 weights 52 gf . Find its apparent if it is fully suspended in water.
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W = 52 gf
Density = 2.6 g/cm3
Vol = 52 ÷ 2.6 = 50 cm3
Density of water = 1 g/cm3
Weight of displaced water= 50 × 1 = 50 gf
Apparent wt= 52-50= 2 gf
Density = 2.6 g/cm3
Vol = 52 ÷ 2.6 = 50 cm3
Density of water = 1 g/cm3
Weight of displaced water= 50 × 1 = 50 gf
Apparent wt= 52-50= 2 gf
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