A piece of aluminium of mass 260g is cooled in a freezer. It is then dropped into 140 g of water at 5°C, causing 4.0g of water to freeze. Determine the temperature inside the freezer.
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Answer:
The equation for heat is
Q=m(tf−ti)Cp
Q = heat in Joules
m = mass in grams
tf = final temp
ti = initial temp
Cp = Specific Heat Capacity
For this problem
Q=???
m=275g
tf=38.4oC
ti=85.2oC
Cp=4.18jgoC
Q=275g(38.4oC−85.2oC)4.18JgoC
Q=275g(−46.8oC))4.18JgoC
Q=−53,796.6J
The negative Joule value means heat is being lost in an exothermic reaction.
Explanation:
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