A piece of bond paper has 21.59 cm and 27.94 cm sides. What is the perimeter of a piece of bond paper?
Answers
Answered by
2
Answer:
Rectangular perimeter:
P = 2(L+W)
= 2 (11 in + 8.5 in)
= 2 ( 19.5 )
= 39 in
Step-by-step explanation:.
Answered by
0
The perimeter of bond paper is 99.06 cm.
Given - Length and breadth
Find - Perimeter
Solution - Bond paper is rectangular. So, the perimeter will be calculated by finding twice the sum of the sides of the paper.
Perimeter = 2 (21.59 + 27.94)
Performing addition
Perimeter = 2*49.53
Performing multiplication
Perimeter = 99.06
Hence, the perimeter of a piece of bond paper is 99.06 cm.
Similar questions