A piece of cloth costs Rs. 200. If the piece was 5 m longer and each metre of cloth costs Rs. 2 less the cost of the piece would have remained unchanged. How long is the piece and what is the original rate per metre?
Answers
Answer:
SOLUTION:−
\mathsf {Let\:the\:length\:of\:piece = x\:m}Letthelengthofpiece=xm
\mathsf {Rate\:per\:metre = \frac{200}{x}}Ratepermetre=
x
200
\mathsf {New\:length = (x + 5)}Newlength=(x+5)
\mathsf {New\:rate\:per\:metre = \frac{200}{x + 5}}Newratepermetre=
x+5
200
\underline\mathsf \red {ATQ:-}
ATQ:−
\mathsf {\frac{200}{x} - \frac{200}{x + 5} = 2}
x
200
−
x+5
200
=2
\implies \mathsf {\frac{200(x + 5) - 200x}{(x + 5)} = \frac{2}{1} }⟹
(x+5)
200(x+5)−200x
=
1
2
\implies \mathsf {\frac{200x + 1000 - 200x}{x^2 + 5x} = \frac{2}{1} }⟹
x
2
+5x
200x+1000−200x
=
1
2
\implies \mathsf {x^2 + 5x = 500}⟹x
2
+5x=500
\implies \mathsf {x^2 + 5x - 500 = 0}⟹x
2
+5x−500=0
\implies \mathsf {x^2 + 25x - 20x - 500 = 0}⟹x
2
+25x−20x−500=0
\implies \mathsf {x(x + 25) - 20(x + 25) = 0}⟹x(x+25)−20(x+25)=0
\implies \mathsf {(x + 25)\:+ (x - 20) = 0}⟹(x+25)+(x−20)=0
\implies \mathsf {x = -25\:(Neglect) \:or\: x = 20}⟹x=−25(Neglect)orx=20
\mathsf \blue {Rate\:per\:metre = 10}Ratepermetre=10
Step-by-step explanation: