A piece of cloth costs RS 200.If the piece was 5 metre longer and each meter of cloth cost Rs 2 less.the cost of piece would have remained unchanged.
Its from quadratic equation.
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[200/x]-[200/x-5]=2
[1/x]-[1/x+5]=2/200
[5/x²+5x]=1/100
x²+5x=500
x²+5x-500=0
by quadratic equation
-b(+/-)*(√b²-4ac)/2a
-5(+/-)*(√25+2000)/2
-5(+/-)*(√2025)/2
-5(+/-)*(45)/2
-5+45/2 = 40/2 = 20 correct
-5-45/2 = -50/2 = -25 cancel
ans = 20
[1/x]-[1/x+5]=2/200
[5/x²+5x]=1/100
x²+5x=500
x²+5x-500=0
by quadratic equation
-b(+/-)*(√b²-4ac)/2a
-5(+/-)*(√25+2000)/2
-5(+/-)*(√2025)/2
-5(+/-)*(45)/2
-5+45/2 = 40/2 = 20 correct
-5-45/2 = -50/2 = -25 cancel
ans = 20
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