Question

A piece of copper 125kg has a heat capacity of 19687.6J also it is heated from 150 to 250⁰C heat. Find out the specific heat? *​

Answer 1

Explanation:

Q = H X ∆T

19687.6 = H X (250-150)

19687.6 = H X 100

H = 196.876J

AS H = M X S

S = H/M

= 196.876 / 125 JKg^-1⁰c^-1