A piece of copper is shaped into a conductor of minimum resistance. Its length and diameter should be?
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1
Answer:
Since R=
A
ρl
=
π(d/2)
2
ρl
=
πd
2
4ρl
here R is directly depend upon length and inversly depend upon diameter of conductor.
If l becomes
2
l
& d becomes 2d, the new resistance is R
′
=
π(
2
2d
)
2
ρ
2
l
=
2×πd
2
ρl
=
8
R
This is minimum among all the given instances.
Explanation:
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