A piece of copper of mass 40g at 200°C is placed in a copper calorimeter of mass 60g containing 50g of water at 25°C. Ignoring heat losses, what will be the final temperature of the mixture.
(Specific heat capacity of copper= 0.4J/g/K, specific heat capacity of water= 4.2J/g/K )?
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Step-by-step explanation:
The sum of the heats gained is zero.
heatgainedcopper+heat gained calorimeter+heat gained water=0
40*.4*(Tf-200)+60*.4*(Tf-10)+50*4.2*(Tf-10)=0
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