Question

A piece of cork is floating in water contained in a beaker. What is the apparent weight of the cork?

Answer 1

The apparent weight = wt of cork – wt of displaced liquid

In case of cork floating in the liquid, the wt of the cork is equal to the weight of the liquid displaced, i.e. wt of the cork = weight of the displaced liquid.

The apparent weight = weight of the cork – weight of displaced liquid

The apparent weight = 0.